-16x^2+10x+360=0

Solution for -16x^2+10x+360=0 equation:

-16x^2+10x+360=0

a = -16; b = 10; c = +360;
Δ = b2-4ac
Δ = 102-4·(-16)·360
Δ = 23140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{23140}=\sqrt{4*5785}=\sqrt{4}*\sqrt{5785}=2\sqrt{5785}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{5785}}{2*-16}=\frac{-10-2\sqrt{5785}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{5785}}{2*-16}=\frac{-10+2\sqrt{5785}}{-32}
$